The latest news item has a youtube clip which shows a plot of the flight:
Click to view attachment
Assuming that y is N-S and x is E-W, it shows the main S component of the flight but also about a 22m component to the E or W. On the other hand, x returns to close to 0m but the ZCAM image shows that it landed about 10m East of the starting position. Perhaps the internal position tracking drifted during the long flight, in E-W direction only.
If positive x means to S, and negative z up, then positive y would mean to W, I think, in a regular right-handed system. Staring at the Hazcam picture I thought maybe Ingenuity is to the E, closer to the rover not that it is really possible to tell.
I went ahead and sketched out W and E options for a possible flight path in this map:
Click to view attachment
What is interesting that adding a sight line to Ingenuity on the Hazcam image using the hill in the background (long arrow), leads to an intersection really only with the E option. So the circled area is a possible location for Ingenuity on the Hazcam image. It would mean it was close to its destination at 12:34:13. Presumably we will soon know when more images from the flight are released.